How to Retrieve All Maximum Values in a Java Stream
In Java 8, the max function can be used on lambda and streams to identify the maximum value in a dataset. However, when multiple elements have the same maximum value, max arbitrarily chooses and returns one of them.
Expected Behavior:
The goal is to retrieve a list of all elements that share the maximum value, not just a single representative.
Solution:
Since the API lacks an explicit method for this functionality, you can implement a custom solution using intermediate storage and collection manipulation. Here are two approaches:
1. Two-Pass Solution (For Collections):
- Find the maximum value using max and store it.
- Filter the collection to include only elements that match the maximum value.
List<string> list = ... ; int longest = list.stream() .mapToInt(String::length) .max() .orElse(-1); List<string> result = list.stream() .filter(s -> s.length() == longest) .collect(toList());</string></string>
2. Single-Pass Solution (For Streams):
- Employ a custom collector that maintains a list of all elements with the current maximum value during stream processing.
- Return the collected list as the result.
static <t> Collector<t list>> maxList(Comparator super T> comp) { // Implementation goes here (provided in the original response) } Stream<string> input = ... ; List<string> result = input.collect(maxList(comparing(String::length)));</string></string></t></t>
This custom collector tracks intermediate results and updates its state based on each element's value compared to the current maximum. By leveraging this approach, you can obtain a list containing all maximum values from your stream or collection.
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