How Can I Successfully Upload Files Using Python's Requests Library?

Uploading Files with Python Requests

When uploading a file with Python's requests library, you may encounter an issue where the file is not received by the server. To resolve this, follow these steps:

1. Correctly Specify the File Parameter

Ensure that the value of the 'upload_file' keyword is set to the filename, rather than the contents of the file. This should look like:

files = {'upload_file': open('file.txt','rb')}
values = {'DB':'photcat' , 'OUT':'csv' , 'SHORT':'short'}

2. Understand Multi-Part Form POST

Requests will automatically send a multi-part form POST body, where the 'upload_file' field contains the contents of the specified file. The filename will be included in the mime header for this field.

3. Use a Tuple for File Control

If you require more control over the file upload, use a tuple for the files mapping value. This allows you to specify the filename, contents, content-type header, and additional headers. For example:

files = {'upload_file': ('foobar.txt', open('file.txt','rb'), 'text/x-spam')}

4. POST File Directly as Data

If the entire POST body should be taken from a file without specifying additional fields, post the file directly as data:

data = open('file.txt','rb')
headers = {'Content-Type': 'text/plain'}
r = requests.post(url, data=data, headers=headers)

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