How Can We Efficiently Define Powers of 1000 as Constants in Go?

Writing Powers of 10 as Compact Constants

In the context of Go programming, where powers of 2 can be elegantly defined using the iota constant generator, the exercise of declaring constants for powers of 1000 (KB, MB, etc.) presents a challenge due to the absence of an exponentiation operator.

However, there are creative ways to tackle this problem by utilizing other features of the language. One approach involves leveraging floating-point literals with exponents:

const (
    KB, MB, GB, TB, PB, EB, ZB, YB = 1e3, 1e6, 1e9, 1e12, 1e15, 1e18, 1e21, 1e24
)

This method concisely represents all constants in a single line, resulting in a length of 67 characters (excluding spaces).

Another approach employs integer literals and uses the established KB constant as a multiplier:

const (
    KB, MB, GB, TB, PB, EB, ZB, YB = 1000, KB * KB, MB * KB, GB * KB, TB * GB, PB * KB, EB * KB, ZB * KB
)

This approach results in untyped integer constants and has a length of 77 characters (excluding spaces).

Furthermore, by introducing an intermediary constant x to represent the multiplication factor, we can save an additional 3 characters:

const (
    x, KB, MB, GB, TB, PB, EB, ZB, YB = 1000, x, x * x, MB * x, GB * x, TB * GB, PB * x, EB * x, ZB * x
)

This solution achieves a length of 74 characters (excluding spaces).

Lastly, we can utilize rune literals to represent the 1000 constant, which saves another character:

const (
    x, KB, MB, GB, TB, PB, EB, ZB, YB = 'Ϩ', x, x * x, MB * x, GB * x, TB * GB, PB * x, EB * x, ZB * x
)

This approach provides rune constants and has a length of 73 characters (excluding spaces).

These solutions demonstrate various creative techniques to compactly define constant powers of 1000 in the absence of an exponentiation operator in Go.

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