How Can I Skip Arguments in PHP Function Calls While Assigning Values to Subsequent Arguments?

Skipping Arguments in Function Calls

In this scenario, you have a PHP function named getData that accepts three arguments:

function getData($name, $limit = '50', $page = '1') {
    ...
}

Your question is centered around skipping the middle argument ($limit) and assigning a value to the last argument ($page).

To achieve this, you can use a combination of array spread operator and default parameter values. By providing an empty array for the skipped argument, the function will use its default value ('50' for $limit):

getData('some name', [], '23');

While your original approach of passing an empty string for the skipped argument (getData('some name', '', '23')) is syntactically correct, it might not be the best practice. Using an empty array ensures consistency in argument passing and allows for better debugging.

Furthermore, if you need to skip arguments that are not the last ones in the list, you can assign default values to those arguments to indicate that they should be skipped:

function getData($name, $limit = null, $page = null) {
    ...
}

Then, you can skip those arguments using null or an empty string, depending on the context:

getData('some name', null, 23); // Using null for the skipped argument
getData('some name', '', 23); // Using an empty string for the skipped argument

By employing these techniques, you can effectively skip optional arguments in function calls in PHP.

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