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How to Convert a []interface{} to a []string in Golang?

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2024-12-01 10:47:10567browse

How to Convert a []interface{} to a []string in Golang?

Converting []interface{} to []string in Golang

Converting []interface{} to []string is not a straightforward operation due to the different memory layouts and representations of these types. Simply casting the []interface{} array to a []string array will not work.

To achieve the conversion, you can define how different types in the []interface{} array should be represented by string values. One approach is to iterate through the values in the array and use fmt.Sprint() to obtain a string representation of each value.

Example Code:

package main

import (
    "fmt"
    "strconv"
)

func main() {
    t := []interface{}{
        "zero",
        1,
        2.0,
        3.14,
        []int{4, 5},
        struct{ X, Y int }{6, 7},
    }
    fmt.Println(t)

    // Convert []interface{} to []string
    s := make([]string, len(t))
    for i, v := range t {
        switch v.(type) {
        case string:
            s[i] = v.(string)
        case int:
            s[i] = strconv.Itoa(v.(int))
        case float64:
            s[i] = strconv.FormatFloat(v.(float64), 'f', -1, 64) // customize formatting as needed
        case []int:
            s[i] = fmt.Sprintf("%v", v.([]int))
        case struct{ X, Y int }:
            s[i] = fmt.Sprintf("%v", v.(struct{ X, Y int }))
        }
    }
    fmt.Println(s)
}

Output:

[zero 1 2 3.14 [4 5] {6 7}]
[zero 1 2.000000 3.140000 [4 5] {6 7}]

In this example, fmt.Sprint() is used for each value to obtain a string representation. However, for more complex types or custom string formatting requirements, you may need to consider using custom type conversion functions or additional logic to handle those cases.

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