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Partial Template Specialization with Member Functions
When attempting to partially specialize a template for a member function, developers may encounter the error "invalid use of incomplete type." To resolve this, it's essential to understand the limitations of partial specialization in this context.
Error Source
The code below attempts to partially specialize a member function bar for the template foo:
template <typename S, typename T> struct foo { void bar(); }; template <typename T> void foo <int, T>::bar() { }
This code generates an error because partial specialization is not supported for member functions.
Solution
To address this issue, one must partially specialize the entire template instead of just the member function. This can be achieved using the following syntax:
template <typename S, typename T> struct foo { void bar(); }; template <> struct foo <int, T> { void bar(); };
By partially specializing the entire template, the compiler can fully instantiate the specialized version and avoid the incomplete type error.
Note: Partial specializing a function within a template requires more complex workarounds involving nested template members or inheritance from a partially specialized template.
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