How to Efficiently Convert a Byte Array to Hexadecimal in Java?

Converting a Byte Array to Hexadecimal in Java

One can encounter a situation where they need to convert an array of bytes into their corresponding hexadecimal values. Java provides a straightforward method to achieve this conversion efficiently.

Java Implementation

The most concise approach to convert a byte array to hexadecimal is to utilize the StringBuilder class:

byte[] bytes = {-1, 0, 1, 2, 3 };
StringBuilder sb = new StringBuilder();
for (byte b : bytes) {
    sb.append(String.format("%02X ", b));
}
System.out.println(sb.toString());

This code iterates through each byte in the array, converts it to a hexadecimal string with leading zeros (X), and appends it to the string builder. The resulting string contains the hexadecimal values separated by spaces.

Alternative Interpretation

Some scenarios may require converting a string array of decimal values to hexadecimal strings. This can be achieved as follows:

String[] arr = {"-1", "0", "10", "20" };
for (int i = 0; i <p>This code converts each string in the array to a byte, then uses the String.format method to create a hexadecimal string with leading zeros.</p><h3 id="Considerations">Considerations</h3><p>Note that Integer.toHexString(int) can also be used, but be cautious of sign extension when working with negative byte values. Alternatively, the String.format solution is more reliable and flexible.</p>

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