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Executing Linux Shell Built-in Commands from Go Programs
Seeking to validate program existence on Linux, a developer encounters an error upon attempting to execute the "command" utility via a Go program. This error stems from the fact that "command" is a built-in Linux command, not an executable binary in the system's $PATH. The question arises: How can built-in Linux commands be executed within Go programs?
Native Go Solution: exec.LookPath
As suggested in the provided resource, the "command" utility is a shell built-in. For native Go execution, the exec.LookPath function provides a solution. This function searches the system's executable path for the specified command and returns the full path if found.
path, err := exec.LookPath("command") if err != nil { // Handle error } fmt.Println(path) // Prints the full path to the command
Alternative Approaches
If the native Go method is not suitable, alternative approaches exist:
cmd := exec.Command("which", "foobar") out, err := cmd.Output() if err != nil { // Handle error } fmt.Println(string(out)) // Prints the full path to the program (if found)
cmd := exec.Command("/bin/bash", "-c", "command -v foobar") out, err := cmd.Output() if err != nil { // Handle error } fmt.Println(string(out)) // Prints the full path to the program (if found)
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