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Defuse the Bomb

Nov 24, 2024 pm 04:19 PM

Defuse the Bomb

1652. Defuse the Bomb

Difficulty: Easy

Topics: Array, Sliding Window

You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array code of length of n and a key k.

To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.

  • If k > 0, replace the ith number with the sum of the next k numbers.
  • If k th number with the sum of the previous k numbers.
  • If k == 0, replace the ith number with 0.

As code is circular, the next element of code[n-1] is code[0], and the previous element of code[0] is code[n-1].

Given the circular array code and an integer key k, return the decrypted code to defuse the bomb!

Example 1:

  • Input: code = [5,7,1,4], k = 3
  • Output: [12,10,16,13]
  • Explanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7 1 4, 1 4 5, 4 5 7, 5 7 1]. Notice that the numbers wrap around.

Example 2:

  • Input: code = [1,2,3,4], k = 0
  • Output: [0,0,0,0]
  • Explanation: When k is zero, the numbers are replaced by 0.

Example 3:

  • Input: code = [2,4,9,3], k = -2
  • Output: [12,5,6,13]
  • Explanation: The decrypted code is [3 9, 2 3, 4 2, 9 4]. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.

Constraints:

  • n == code.length
  • 1
  • 1
  • -(n - 1)

Hint:

  1. As the array is circular, use modulo to find the correct index.
  2. The constraints are low enough for a brute-force solution.

Solution:

We can implement a function that iterates over the code array and computes the sum of the appropriate numbers based on the value of k.

The general approach will be as follows:

  1. If k == 0, replace all elements with 0.
  2. If k > 0, replace each element with the sum of the next k elements in the circular array.
  3. If k

The circular nature of the array means that for indices that exceed the bounds of the array, you can use modulo (%) to "wrap around" the array.

Let's implement this solution in PHP: 1652. Defuse the Bomb

<?php /**
 * @param Integer[] $code
 * @param Integer $k
 * @return Integer[]
 */
function decrypt($code, $k) {
    ...
    ...
    ...
    /**
     * go to ./solution.php
     */
}

// Example Usage
$code1 = [5, 7, 1, 4];
$k1 = 3;
print_r(decrypt($code1, $k1)); // Output: [12, 10, 16, 13]

$code2 = [1, 2, 3, 4];
$k2 = 0;
print_r(decrypt($code2, $k2)); // Output: [0, 0, 0, 0]

$code3 = [2, 4, 9, 3];
$k3 = -2;
print_r(decrypt($code3, $k3)); // Output: [12, 5, 6, 13]
?>

Explanation:

  1. Initialization:

    • We create a result array initialized with zeros using array_fill.
  2. Handling k == 0:

    • If k is zero, the output array is simply filled with zeros, as required by the problem.
  3. Iterating Through the Array:

    • For each index i in the array:
      • If k > 0, sum the next k elements using modulo arithmetic to wrap around.
      • If k
  4. Modulo Arithmetic:

    • We use ($i $j) % $n to wrap around to the beginning of the array when accessing indices greater than n - 1.
    • Similarly, ($i - $j $n) % $n handles backward wrapping for negative indices.
  5. Complexity:

    • Time Complexity: O(n . |k|), where n is the size of the array and |k| is the absolute value of k.
    • Space Complexity: O(n) for the result array.

Outputs:

The provided examples match the expected results. Let me know if you need further explanation or optimizations!

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