How Can I Efficiently Check if Any or All List Elements Meet a Specific Condition in Python?

Efficiently Checking if Any Element of a List Matches a Condition

Your code snippet contains a while loop that iterates over a list to check if any of its elements meets a specific condition, specifically if the last element of each sub-list is 0. To improve efficiency and readability, consider using Python's built-in functions all() and any() to handle such checks.

Using all()

The all() function returns True if all elements in a list evaluate to True when applied with a given condition. In your case, to check if all elements have a flag value of 0, you can use:

all(item[2] == 0 for item in list_)

This expression returns True if all sub-lists have a flag of 0, and False otherwise.

Using any()

On the other hand, the any() function returns True if any element in a list evaluates to True when applied with a given condition. To check if at least one sub-list has a flag value of 0:

any(item[2] == 0 for item in list_)

This expression returns True if any of the sub-lists have a flag of 0, and False otherwise.

Example Usage

my_list = [[1, 2, 0], [2, 3, 1], [4, 5, 0]]
if all(item[2] == 0 for item in my_list):
    print("All flags are 0")
else:
    print("At least one flag is not 0")

if any(item[2] == 0 for item in my_list):
    print("At least one flag is 0")
else:
    print("No flags are 0")

In this example, the output would be:

At least one flag is not 0
At least one flag is 0

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