Home >Java >javaTutorial >Why Does My Java String `replace()` Method Not Seem to Work?

Why Does My Java String `replace()` Method Not Seem to Work?

Patricia Arquette
Patricia ArquetteOriginal
2024-11-19 21:59:03746browse

Why Does My Java String `replace()` Method Not Seem to Work?

Java String replace Method Failure [Duplicate]

Certain Java implementations have reported the replace() method failing to adequately replace specific strings within a given String. This anomaly occurs due to the immutable nature of String objects.

Analysis of the Problematic Code:

In the provided code snippet:

<br>String delimiter = "<em></em>";<br>String html = "<html><head></head><body><strong>USERNAME</strong> AND <strong>PASSWORD</strong></body></html>";<br>Map<String, String> mp = new HashMap<String, String>();<br>mp.put("USERNAME", "User A");<br>mp.put("PASSWORD", "B");<br>for (Entry<String, String> entry : mp.entrySet()) {<br>  html.replace(delimiter   entry.getKey()  delimiter, entry.getValue());<br>}<br>

Explanation of the Issue:

The replace() method in Java does not mutate the original String object. Instead, it returns a new String with the replacements applied. This is the point of contention: the original html variable continues to hold the original String value.

Resolution:

To rectify this, the code should be modified to explicitly reassign the html variable with the result of the replace() operation:

<br>html = html.replace(delimiter   entry.getKey()  delimiter, entry.getValue());<br>

Conclusion:

Understanding the immutability of String objects is crucial when utilizing methods like replace(). Assigning the returned String object to the original variable ensures the intended replacements take effect.

The above is the detailed content of Why Does My Java String `replace()` Method Not Seem to Work?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn