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Why Does Go Regex Throw a "Invalid or Unsupported Perl Syntax: (?!" Error and How to Work Around It?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2024-11-16 17:52:03831browse

Why Does Go Regex Throw a

Go Regex Parsing Error: (?!

When attempting to compile the following regex in Go, an error occurs:

error parsing regexp: invalid or unsupported Perl syntax: (?!

This error stems from the fact that the Go regex engine does not support lookarounds, a Perl-specific syntax. Lookarounds are regex patterns that check for the presence or absence of specific patterns around the current position, making them indispensable for certain complex text matching tasks.

Workaround

As Go does not natively support lookarounds, the workaround involves manually checking for the presence or absence of specific patterns. For the provided regex:

^(?!On.*On\s.+?wrote:)(On\s(.+?)wrote:)$

The following approach can be employed:

  • Use two separate regex patterns to check for the presence (second pattern) and absence (first pattern) of the desired pattern.
  • Compile the patterns:
absencePattern := regexp.MustCompile("^(?!On.*On\s.+?wrote:)(On\s(.+?)wrote:)$")
presencePattern := regexp.MustCompile("^(On.*On\s.+?wrote:$")
  • Perform the checks on the input string:
if absencePattern.MatchString(input) && !presencePattern.MatchString(input) {
  // The pattern is absent
} else {
  // The pattern is present
}

Additional Option

Alternatively, you could use an optional capturing group to achieve the same result:

pattern := regexp.MustCompile(`^On(.*On)?\s.+?wrote:`)
if match := pattern.FindStringSubmatch(input); match != nil { // match is nil if no match found
  if match[1] != "" { // Group 1 ends with "On"
    return false
  }
  return true
}

This approach eliminates the need for separate regex patterns, simplifying the code while maintaining the desired functionality.

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