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How do I parse server-side errors and display them in a dialog box using jqGrid?

Linda Hamilton
Linda HamiltonOriginal
2024-11-14 18:50:03643browse

How do I parse server-side errors and display them in a dialog box using jqGrid?

Handling Server-Side Errors and Validation in jqGrid

Question:

In my JSON responses, I have "STATUS" and "errors" properties. How can I utilize these properties in jqGRid to parse errors and display them in a dialog box?

Answer:

The key to handling errors with jqGrid is to follow HTTP protocol rules. Successful responses include a status code of 200, while error responses have specific status codes (e.g., 404 Not Found).

Error Handling Implementation:

In your loadError event handler, you can check the HTTP status code and parse the response accordingly:

loadError: function (jqXHR, textStatus, errorThrown) {
    if (jqXHR.status === 404) {
        // Error handling for 404 Not Found
    } else if (typeof jqXHR.responseText === "string") {
        // Error handling based on the JSON response
        var errorInfo = $.parseJSON(jqXHR.responseText);
        var errorMessages = "";
        for (var i = 0; i < errorInfo.length; i++) {
            errorMessages += errorInfo[i].Source + ": " + errorInfo[i].Message;
        }
        alert("Error:\n" + errorMessages);
    }
}

Note: You can customize the error message display to match your application's needs using HTML or CSS.

Additional Considerations:

  • If you send errors as JSON, ensure the Content-Type header is set to application/json.
  • Free jqGrid also provides a default loadError implementation that displays a readable error message in an error div above the grid.
  • You can use the displayErrorMessage method to set custom error messages in the error div.

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