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Fallthrough in Type Switches: Why It's Not Permitted
In Go's type switch statement, the "fallthrough" keyword is prohibited. The official documentation briefly states this restriction without providing an in-depth explanation. This article aims to delve into the potential reasons behind this constraint.
Understanding the Issue
In a type switch, each case statement evaluates an expression of type interface{} to a specific type. The value of the expression is then bound to the specified type for use within the case block. However, fallthrough can lead to confusion because of the varying types associated with each case.
Consider the following example:
var x interface{} x = bool(true) switch i := x.(type) { case int: fmt.Println(i + 1) // Error: cannot use bool as int case float64: fmt.Println(i + 2.0) // Error: cannot use bool as float64 case bool: fallthrough case string: fmt.Printf("%v", i) // Error: cannot use bool as string }
In this scenario, the variable i would have a different type depending on which case is encountered. When fallthrough is used, the subsequent case statement would expect a variable of the same type as the previous case. However, if the previous case was bool and fallthrough is used, the subsequent case would encounter a value of type string, leading to type mismatch errors.
Possible Reasons
Alternative Approaches
If a developer requires the functionality of fallthrough in a type switch, there are alternative approaches to achieve similar results:
switch i := x.(type) { case int, float64: fmt.Println(i) }
switch i := x.(type) { case bool: if i { fmt.Println("True") } }
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