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How to Stream Zip Files Dynamically on a LAMP Stack Without Creating Temporary Files?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2024-11-07 14:42:03270browse

How to Stream Zip Files Dynamically on a LAMP Stack Without Creating Temporary Files?

How to Stream Zip Files Dynamically on a LAMP Stack

The Challenge

Creating archives of large files on-the-fly in a web service can lead to performance issues and resource constraints. Traditional methods involve creating temporary zip files, resulting in CPU, disk, and memory overhead.

Streaming Solution with popen() and flush()

To avoid these drawbacks, consider streaming the zip file creation directly to the user. This can be achieved using popen() or proc_open() to execute a streaming pipeline command (e.g., zip). Combining this with flush() allows for efficient streaming of the zip file as it is being created.

Revised Example

Here's an updated code example that addresses some caveats raised by @Benji in the comments:

<?php
// Set headers
header('Content-Type: application/octet-stream');
header('Content-disposition: attachment; filename="file.zip"');
mb_http_output('pass');

// Execute pipeline command using popen()
$fp = popen('zip -r - file1 file2 file3', 'r');

// Initialize buffer
$bufsize = 8192;

// Stream zip file
while (!feof($fp)) {
    $buff = fread($fp, $bufsize);
    echo $buff;
}

// Close process
pclose($fp);

Note: While flush() was initially recommended, it's advisable to avoid using it within the loop for large files or slow networks. This can lead to buffer overrun issues.

Additional Considerations

For multi-processor servers, consider using nodeJS with the http and child_process modules for efficient, non-blocking I/O.

Setting the Content-Length header is not possible in this scenario as the zip file size is unknown beforehand. However, consider investigating if there are headers that indicate streaming or unknown content length.

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