How to Get Precisely Truncated Float Values?
Truncating float values, or removing digits beyond a specified number of decimal places, is a common operation in programming. However, achieving accurate truncation without rounding can be challenging due to the limitations of floating-point representation.
Understanding the Issue
Consider the example:
1.923328437452 -> 1.923
A naive approach would be to convert the float to a string and truncate it, but this can lead to errors due to the imprecise nature of floating-point representations. Different floating-point values may have the same binary representation, resulting in ambiguous truncation.
The Recommended Method
For Python versions 2.7 and above, the following function provides accurate truncation without rounding:
def truncate(f, n): '''Truncates/pads a float f to n decimal places without rounding''' s = '{}'.format(f) if 'e' in s or 'E' in s: return '{0:.{1}f}'.format(f, n) i, p, d = s.partition('.') return '.'.join([i, (d+'0'*n)[:n]])
Explanation
The core of this method is to convert the float to a string using '{}'.format(f) and truncate the string to the desired number of decimal places. For values in scientific notation ('e' or 'E'), the '{0:.{1}f}'.format(f, n) syntax is used to specify the precision.
Handling Special Cases
In rare cases, floats very close to round numbers may still be truncated incorrectly. For such cases, specify a higher precision to ensure that rounding during string conversion does not affect the result.
Alternatives for Older Python Versions
For Python versions below 2.7, a less accurate method involves rounding the float to 12 decimal places before truncation:
def truncate(f, n): '''Truncates/pads a float f to n decimal places without rounding''' s = '%.12f' % f i, p, d = s.partition('.') return '.'.join([i, (d+'0'*n)[:n]])
Conclusion
This code provides a robust solution for truncating float values without rounding, ensuring accurate truncation for a wide range of inputs.
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