How do you extract data from a MySQL query result in PHP and avoid the \"Resource id #\" issue?

Extracting Data from MySQL Query: Overcoming "Resource id #" Issue

In PHP, when executing a MySQL query using the mysql_query() function, the result is stored as a resource identifier. To access the actual data from the query, a fetch function like mysql_fetch_assoc() must be employed.

Original Code and Issue:

<code class="php">$datos1 = mysql_query("SELECT TIMEDIFF(NOW(), '" . $row['fecha'] . "');");
echo($datos1);</code>

However, this code doesn't provide the expected results. Instead, it prints "Resource id #6," which indicates that the query result is a resource rather than the actual data.

Solution: Using Fetch Function:

To extract the data from the query, use a fetch function like mysql_fetch_assoc() as follows:

<code class="php">$result = mysql_query(sprintf("SELECT TIMEDIFF(NOW(), '%s') as time_delta", $row['fecha']));
if ($result) {
    $data = mysql_fetch_assoc($result);
    echo $data['time_delta'];
}</code>

Note:

While the mysql functions are still supported in PHP, their use is discouraged. Instead, consider using PDO with PDO_MYSQL or MySQLi for better performance, security, and compatibility with future versions of PHP.

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