How to Define a Template Member Function Outside of the Class Definition?

Defining a Template Member Function Outside of the Class Definition

In template programming, it can be necessary to define a template member function outside of the class definition while maintaining access to both template parameters.

Consider the following code snippet:

<code class="cpp">template <class T>
class Foo
{
public:
    template <class U>
    void bar();
};</code>

To implement the bar function outside of the class definition, we can use the following syntax:

<code class="cpp">template<class T> template <class U>
void Foo<T>::bar() { ... }</code>

This syntax tells the compiler that the bar function is a member function of the Foo class with a template parameter T. Within the definition of bar, we can access both T and the additional template parameter U as needed.

For example:

<code class="cpp">template<class T> template <class U>
void Foo<T>::bar()
{
    std::cout << "T: " << typeid(T).name() << ", U: " << typeid(U).name() << std::endl;
}</code>

This code will print the names of the T and U template parameters when the bar function is called.

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