How to Print Addresses with Char Pointers Using `cout`?

Cout Interpretation of Char Pointers

Unlike printf(), which offers specific conversion specifiers (%u or %s) to determine whether to print an address or the entire string pointed to by a char pointer, cout requires an explicit approach for this distinction.

Example Problem:

Consider the following code snippet:

<code class="cpp">int main() {
  char ch = 'a';
  char *cptr = &ch;
  cout <p>In this example, with the default GNU compiler, cout interprets the char pointer as a C-style string and attempts to print the character pointed to by cptr. However, if the intention is to print the address of ch instead, a different approach is necessary.</p>
<p><strong>Solution:</strong></p>
<p>To print the address of ch using cptr with cout, explicit type casting is required. This is achieved by utilizing the static_cast operator, as demonstrated below:</p>
<pre class="brush:php;toolbar:false"><code class="cpp">cout (cptr) <p>By explicitly casting cptr to void *, the overload resolution selects the appropriate ostream& operator that takes a void pointer as an argument. This correctly prints the address of ch.</p></code>

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