How to Parse ISO 8601 String with Missing Colon in Offset in Java 8?

Parsing ISO 8601 String without Colon in Offset to Java 8 Date

The issue arises when attempting to parse an ISO 8601-formatted string with an offset lacking a colon (e.g., "2018-02-13T10:20:12.120 0000") using the new date-time API in Java 8.

Solution

Until bug is fixed (Java 8)

Use a workround:

• Hack: Insert colon in input string:

<code class="java">String input = "2018-02-13T10:20:12.120+0000".replace( "+0000" , "+00:00" );
OffsetDateTime odt = OffsetDateTime.parse( input );</code>

• Explicit formatting pattern:

<code class="java">String input = "2018-02-13T10:20:12.120+0000" ;
DateTimeFormatter f = DateTimeFormatter.ofPattern( "uuuu-MM-dd'T'HH:mm:ss.SSSX" );
OffsetDateTime odt = OffsetDateTime.parse( input , f );</code>

When bug is fixed:

To parse without workarounds:

<code class="java">OffsetDateTime odt = OffsetDateTime.parse( "2018-02-13T10:20:12.120+0000" );</code>

Additional Notes:

• Avoid legacy date-time classes like java.util.Date and SimpleDateFormat.
• Use OffsetDateTime for offsets and Instant for UTC values.
• For time zone conversion, use ZonedDateTime.
• Review Stack Overflow for additional examples and information.

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