


How to Initialize a Slice of Pointers to Structs in Go: A Breakdown of Anonymous Struct Syntax?
Initializing Slice of Pointers: Understanding Anonymous Struct Syntax
In Chapter 7 of GOPL, an example is given for initializing a slice of pointers to Track structs:
var tracks = []*Track{ {"Go", "Delilah", "From the Roots Up", 2012, length("3m38s")}, {"Go", "Moby", "Moby", 1992, length("3m37s")}, {"Go Ahead", "Alicia Keys", "As I Am", 2007, length("4m36s")}, {"Ready 2 Go", "Martin Solveig", "Smash", 2011, length("4m24s")}, }
To understand the syntax, let's examine the following code where we define a custom Ex struct and initialize its slices:
type Ex struct { A, B int } a := []Ex{Ex{1, 2}, Ex{3, 4}} b := []Ex{{1, 2}, {3, 4}} c := []*Ex{&Ex{1, 2}, &Ex{3, 4}} d := []*Ex{{1, 2}, {3, 4}} e := []*Ex{{1, 2}, &Ex{3, 4}}
In cases a and b, we initialize the slices with instances of the Ex struct using a shortcut syntax:
f := []<type>{{...}, {...}}</type>
This is equivalent to:
f := []<type>{<type>{...}, <type>{...}}</type></type></type>
For cases c, d, and e, the syntax requires a bit more explanation. The initialization:
f := []*<type>{{...}, {...}}</type>
Is analogous to:
f := []*<type>{&<type>{...}, &<type>{...}}</type></type></type>
In other words, the curly braces following the type specify the values for a struct of that type, and the ampersands create pointers to those structs.
Finally, in the following code, we receive a syntax error:
f := []*Ex{&{1, 2}, &{3, 4}} // Syntax Error!
This is because the curly braces must be followed by the name of a type, not an anonymous struct. The correct syntax would be:
f := []*Ex{&Ex{1, 2}, &Ex{3, 4}}
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