How to Fix the \"Specified Child Already Has a Parent\" Error in Android?

Android: Addressing "Specified Child Already Has a Parent" Error

When attempting to switch between layouts repeatedly, you may encounter an error stating, "The specified child already has a parent. You must call removeView() on the child's parent first." This arises when you try to add a view to a layout without first removing it from its previous parent.

Error Trigger

The error typically occurs when switching between layouts that contain the same views. For instance, you might have a TextView (tv) in both layouts. When you switch to the second layout, the error appears when you attempt to add tv to it again without removing it from the first layout.

Layout Code

Your layout code, as provided in the question, attempts to add tv to a LinearLayout:

<code class="java">// TEXTVIEW
layout.addView(tv);</code>

However, during subsequent runs, tv already has a parent (the LinearLayout from the previous layout), leading to the error.

Solution

To resolve this issue, you need to remove tv from its previous parent before adding it to the new one. This can be achieved by:

<code class="java">// TEXTVIEW
if (tv.getParent() != null) {
    ((ViewGroup) tv.getParent()).removeView(tv); // <- fix
}
layout.addView(tv);</code>

This code checks if tv already has a parent, and if it does, it removes it from that parent before adding it to the current LinearLayout.

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