How to Extract Subject DN from X509 Certificate in Go
Retrieving the complete subject distinguished name (DN) from an X509 certificate in Go as a string can be challenging. Despite lacking a dedicated ".String()" method for the pkix.Name type, there is a multifaceted solution.
Solution:
The following function leverages a predefined map to translate OIDs into meaningful field names (e.g., "CN" for Common Name):
<code class="go">import ( "fmt" "strings" "crypto/x509" "crypto/x509/pkix" ) var oid = map[string]string{ "2.5.4.3": "CN", "2.5.4.6": "C", "2.5.4.7": "L", "2.5.4.8": "ST", "2.5.4.10": "O", "2.5.4.11": "OU", "1.2.840.113549.1.9.1": "emailAddress", } func getDNFromCert(namespace pkix.Name, sep string) (string, error) { subject := []string{} for _, s := range namespace.ToRDNSequence() { for _, i := range s { if v, ok := i.Value.(string); ok { if name, ok := oid[i.Type.String()]; ok { subject = append(subject, fmt.Sprintf("%s=%s", name, v)) } else { subject = append(subject, fmt.Sprintf("%s=%s", i.Type.String(), v)) } } else { subject = append(subject, fmt.Sprintf("%s=%v", i.Type.String(), v)) } } } return sep + strings.Join(subject, sep), nil }</code>
Usage:
To extract the subject DN, invoke the function as follows:
<code class="go">subj, err := getDNFromCert(x509Cert.Subject, "/") if err != nil { // Error handling } fmt.Println(subj)</code>
Example Output:
/C=US/O=some organization/OU=unit/CN=common name
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