How Do You Sort a JavaScript Object by Property Name Alphabetically?

Sorting a JavaScript Object by Property Name Revisited

In JavaScript, objects are unordered collections of key-value pairs. While accessing a property by its key, the order of keys is insignificant and not guaranteed. However, there are scenarios where sorting an object by its property names alphabetically becomes desirable.

Sorting Techniques

Traditionally, sorting an object by its property names required converting it to an array of keys, sorting the array alphabetically, and then reconstructing the object. This approach used a loop and involved creating a temporary array, which could impact performance for large objects.

In ES6, however, objects became ordered. This meant that iterating over an object's keys would return them in the order they were defined. Consequently, sorting an object's keys became as simple as:

<code class="javascript">const sortedObject = Object.fromEntries(
  Object.entries(originalObject).sort(([a], [b]) => a.localeCompare(b))
);</code>

In this example, Object.entries() converts the object into an array of key-value pairs. Then, sort() sorts the array alphabetically based on the property names using localeCompare() for case-insensitive sorting. Finally, Object.fromEntries() reconstructs the object with the sorted property names.

Note: ES6 objects are ordered only if they are created using a literal { } or if they inherit from an ordered object. Objects created using Object.create(null) are still unordered.

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