Home >Java >javaTutorial >Can We Create Generic Arrays in Java That Extend Comparable?
Introduction
Generic arrays, where the array elements share a common type parameter, present a unique challenge in Java due to the interplay between generics and arrays' covariant behavior.
Question
Can we create an array of generics where the generic type extends Comparable? Attempts to cast an Object array to a generic array that extends Comparable face issues, raising the following question: Is there a workaround?
Answer
Generics and Arrays: A Compatibility Puzzle
Generics and arrays have fundamentally different ways of handling types:
Due to this mismatch, creating an array of generic types that extend a specific class is not possible.
Array.newInstance(): A Workaround
One potential solution is to use the Array.newInstance() method:
<code class="java">private Comparable[] hashtable; ... hashtable = (Comparable[])Array.newInstance(Comparable.class, tableSize);</code>
This approach allows you to create an array of the generic type's supertype (Comparable in this case), but it's important to note that this array is not of the desired generic type.
Why Not Use Arrays with Generics?
While there are workarounds, using arrays with generics is generally discouraged due to:
Alternative: ArrayList
A more suitable option is to use ArrayList, which provides an efficient and type-safe way to manage collections of generic objects. ArrayLists offer the flexibility of generics and avoid the potential pitfalls associated with arrays and generics.
The above is the detailed content of Can We Create Generic Arrays in Java That Extend Comparable?. For more information, please follow other related articles on the PHP Chinese website!