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How to Display a Unique Random Product from Firebase Without Downloading All Data?

Susan Sarandon
Susan SarandonOriginal
2024-10-27 22:27:021065browse

 How to Display a Unique Random Product from Firebase Without Downloading All Data?

How to Get a Unique Random Product in Node Firebase?

Data:

- products
   - -L74Pc7oVY22UsCETFBv
       - name: "gjwj"
       - category: "hreggrrg"
       - location: "vjhiwehifwe"
       - price: 44
       - color: fassaf
   - -L74uJ7oVYcVNyCteFBz
       - name: "uygfwh"
       - category: "hhhjwwwom"
       - location: "pervrr"
       - price: 33
       - color: yrtrr
   ......................

Challenge:

You want to display only one unique random product to the user, avoiding the need to download all the products.

Solution 1: Classic Approach

  1. Add child("products") to your reference to target the correct node in the database.
  2. Iterate through all the child nodes of the products node.
  3. Add the names of the products to a list.
  4. Get a random index within the list size.
  5. Add the product at the random index to the randomProductList.
<code class="java">DatabaseReference productsRef = rootRef.child("products");
ValueEventListener valueEventListener = new ValueEventListener() {
    @Override
    public void onDataChange(DataSnapshot dataSnapshot) {
        List<String> productList = new ArrayList<>();
        for(DataSnapshot ds : dataSnapshot.getChildren()) {
            String name = ds.child("name").getValue(String.class);
            productList.add(name);
        }

        int productListSize = productList.size();
        List<String> randomProductList = new ArrayList<>();

        randomProductList.add(new Random().nextInt(productListSize)); //Add the random product to list

        // Update the adapter with the random product
        arrayAdapter.notifyDatasetChanged();
    }

    @Override
    public void onCancelled(DatabaseError databaseError) {
        Log.d(TAG, "Error: ", task.getException()); //Don't ignore errors!
    }
};
productsRef.addListenerForSingleValueEvent(valueEventListener);</code>

Solution 2: Denormalization Approach

  1. Create a new node called productIds within the database.
  2. Add a key for each product ID under the productIds node.
  3. Query the productIds node to get the product IDs.
  4. Generate a random index within the number of product IDs.
  5. Query the products node using the random product ID to get the product details.
<code class="java">DatabaseReference productIdsRef = rootRef.child("productIds");
ValueEventListener valueEventListener = new ValueEventListener() {
    @Override
    public void onDataChange(DataSnapshot dataSnapshot) {
        List<String> productIdsList = new ArrayList<>();
        for(DataSnapshot ds : dataSnapshot.getChildren()) {
            String productId = ds.getKey();
            productIdsList.add(productId);
        }

        int productListSize = productList.size();
        String randomProductId = productIdsList.get(new Random().nextInt(productListSize));

        DatabaseReference productIdRef = rootRef.child("products").child(randomProductId);
        ValueEventListener eventListener = new ValueEventListener() {
            @Override
            public void onDataChange(DataSnapshot dataSnapshot) {
                String name = dataSnapshot.child("name").getValue(String.class);
                Log.d("TAG", name); // Output the random product name
            }

            @Override
            public void onCancelled(DatabaseError databaseError) {
                Log.d(TAG, "Error: ", task.getException()); //Don't ignore errors!
            }
        };
        productIdRef.addListenerForSingleValueEvent(eventListener);
    }

    @Override
    public void onCancelled(DatabaseError databaseError) {
        Log.d(TAG, "Error: ", task.getException()); //Don't ignore errors!
    }
};
productIdsRef.addListenerForSingleValueEvent(valueEventListener);</code>

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