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Here are a few title options, tailored to be question-based and reflect the article\'s content: Option 1 (Focus on the Problem): * Why Does My Vector Only Store the First User Input? Option 2 (Focus

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2024-10-26 13:51:31719browse

Here are a few title options, tailored to be question-based and reflect the article's content:

Option 1 (Focus on the Problem):
* Why Does My Vector Only Store the First User Input?

Option 2 (Focus on the Solution):
* How to Continuously Store User Inp

How to Continuously Store User Input into a Vector

When working with user input, it's common to want to store it in a vector for further processing. However, in the following code snippet, only the first user-provided number is captured:

<code class="cpp">int main() {
  int input;
  vector<int> V;
  cout << "Enter your numbers to be evaluated: " << endl;
  cin >> input;
  V.push_back(input);
}</code>

To address this issue, the code needs to continuously read user input until a specific condition is met (e.g., the user types a specific character or the end of the input stream is reached).

Solution 1: Using a While Loop with cin

The following code uses a while loop to continuously read integers from the user and push them into the vector:

<code class="cpp">while (cin >> input) {
  V.push_back(input);
}</code>

Solution 2: Using a Sentinel Value with cin

Another approach is to use a sentinel value that signifies the end of input. In this example, we'll use 9999:

<code class="cpp">while ((cin >> input) && input != 9999) {
  V.push_back(input);
}</code>

This loop will continue reading input until the user types 9999 or any other value that renders cin invalid.

By implementing these solutions, you can effectively store all user-provided numbers in a vector for further processing.

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