How to Fix \"TypeError: view must be a callable or list/tuple\" in Django URLs?

Error in Django URLs: Understanding the "TypeError: view must be a callable or a list/tuple in the case of include()"

Upgrading to Django 1.10 can lead to an error related to the format of view definitions in URL patterns:

TypeError: view must be a callable or a list/tuple in the case of include().

Cause:

Prior to Django 1.10, views could be specified as strings referring to their location within a module, such as 'myapp.views.home'. However, this practice is no longer supported.

Solution:

In Django 1.10 and later, view definitions must be provided as callable functions or a list/tuple of callable functions. This means you'll need to either:

1. Import the View Function:

Update your urls.py to import the view function explicitly and provide it as the callable:

<code class="python">from myapp.views import home

urlpatterns = [
    url(r'^$', home, name='home'),
]</code>

2. Import the Views Module and Use Aliases:

If you have multiple views in a single module, you can import the entire module and use aliases to access the specific views:

<code class="python">from myapp import views as myapp_views

urlpatterns = [
    url(r'^$', myapp_views.home, name='home'),
]</code>

Importing Views from Other Apps:

If the views you want to use are located in another app, you can import the app's views module and use the same technique as above:

<code class="python">from another_app import views as another_app_views

urlpatterns = [
    url(r'^$', another_app_views.my_view, name='my_view'),
]</code>

Note: When importing views this way, it's recommended to use aliases (e.g., as another_app_views) to avoid any conflicts with views defined in your own app.

Additional Information:

For more details on defining URL patterns in Django, please refer to the Django URL dispatcher documentation: https://docs.djangoproject.com/en/stable/topics/http/urls/

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