How to Resolve Django\'s TypeError: view must be a callable in URL Patterns?

Django URL Patterns: Understanding the TypeError: view must be a callable

For Django versions 1.10 onwards, a specific error message may arise when defining URL patterns: TypeError: view must be a callable or a list/tuple in the case of include(). This error occurs when attempting to specify views as strings within URL patterns, a practice commonly used in earlier Django versions.

Solution:

To resolve this error, it is necessary to update your urls.py to include the actual view callable. This requires importing the view within your urls.py file. For example:

from django.conf.urls import include, url

from django.contrib.auth.views import login
from myapp.views import home, contact

urlpatterns = [
    url(r'^$', home, name='home'),
    url(r'^contact/$', contact, name='contact'),
    url(r'^login/$', login, name='login'),
]

Alternative Solution:

If you have a large number of views, importing them individually can become inconvenient. An alternative approach is to import the views module from your app:

from django.conf.urls import include, url

from django.contrib.auth import views as auth_views
from myapp import views as myapp_views

urlpatterns = [
    url(r'^$', myapp_views.home, name='home'),
    url(r'^contact/$', myapp_views.contact, name='contact'),
    url(r'^login/$', auth_views.login, name='login'),
]

Using aliases such as myapp_views and auth_views prevents view name collisions when importing views from multiple apps.

Additional Information:

For more comprehensive information about URL dispatching patterns, refer to the official Django URL dispatcher documentation:

[Django URL dispatcher docs](https://docs.djangoproject.com/en/stable/topics/http/urls/)

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