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Floating-Point Range in Python
Python's built-in range() function allows you to generate a sequence of integers. However, when working with floating-point numbers, a straight-up range() won't suffice.
Problem: Non-Integer Step Size
Using range() with a floating-point as the step argument results in an error:
<code class="python">>>> range(0.5, 5, 0.5) Traceback (most recent call last): File "<pyshell#10>", line 1, in <module> range(0.5, 5, 0.5) ValueError: range() step argument must not be zero</code>
This is because range() requires the step size to be an integer.
Solution: Division-Based List Comprehensions
One way to create a floating-point range is through list comprehensions combined with division:
<code class="python">[x / 10.0 for x in range(5, 50, 15)]</code>
This comprehension divides each element in the range(5, 50, 15) by 10.0 to produce a floating-point sequence.
Alternative: Map and Lambda
Another method involves using the map() function and a lambda expression:
<code class="python">map(lambda x: x / 10.0, range(5, 50, 15))</code>
Here, the lambda expression converts each number in the range to a float by dividing it by 10.0. map() applies this function to all elements in the range, resulting in a floating-point sequence.
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