Home > Article > Backend Development > How to Resolve \"FileNotFoundError: No Such File or Directory\" When Parsing CSV Files?
Unable to Locate CSV File: "FileNotFoundError: [Errno 2] No Such File or Directory [Duplicate]"
When attempting to parse a CSV file, developers may encounter the "FileNotFoundError: [Errno 2] No Such File or Directory" exception, indicating that Python cannot locate the specified file.
To resolve this issue, it's crucial to understand the concept of relative and absolute paths. When opening a file with a relative path, such as "address.csv" in the given code, Python assumes the file is located in the current working directory.
To verify the current working directory, add the following snippet to your code:
<code class="python">import os cwd = os.getcwd() # Get the current working directory (cwd) files = os.listdir(cwd) # Get all the files in that directory print("Files in %r: %s" % (cwd, files))</code>
Alternatively, you can specify the exact location of the file using an absolute path, such as:
<code class="python">f = open("/Users/foo/address.csv") # Replace with the full path to the CSV file</code>
By utilizing an absolute path, you explicitly instruct Python where to find the file, avoiding the need for assumptions based on the current working directory.
The above is the detailed content of How to Resolve \"FileNotFoundError: No Such File or Directory\" When Parsing CSV Files?. For more information, please follow other related articles on the PHP Chinese website!