Two common javascript array deduplication methods, ideas and codes_javascript skills

The first is a more conventional method
Ideas:
1. Construct a new array to store the results
2. Take one out of the original array each time in the for loop element, use indexOf to find whether the element exists in the new array
3. If not, store it in the result array

Copy code The code is as follows:

Array.prototype.unique1 = function(){
var res = [];
for(var i = 0; i if(res.indexOf(this[i]) == -1){
res.push(this[i]);
}
}
return res;
}
var arr = [1, 'a', 'a', 'b', 'd', 'e', ​​'e', ​​1, 0]
alert(arr.unique1( ))

This basis can be slightly optimized, but the principle remains the same and the effect is not obvious

Copy code The code is as follows:

Array.prototype.unique1 = function(){
var res = [this[0]];//Directly change the first element in the original array Store in the new array constructed
for(var i = 1; i if(res.indexOf(this[i]) == -1){
res.push(this[i]);
}
}
return res;
}
var arr = [1, 'a', 'a', 'b', 'd', 'e', ​​'e', ​​1, 0]
alert(arr.unique1())

Second The method is more efficient than the above method
Ideas:
1. Sort the original array first
2. Check whether the i-th element in the original array is the last element in the result array The same, because it has been sorted, the duplicate elements will be in adjacent positions
3. If they are not the same, the element will be stored in the result array

Copy code The code is as follows:

Array.prototype.unique2 = function(){
this.sort(); // Sort first
var res = [ this[0]];
for(var i = 1; i if(this[i] !== res[res.length - 1]){
res.push(this[i]);
}
}
return res;
}
var arr = [1, 'a', 'a', 'b', 'd', 'e', ​​'e', ​​1, 0]
alert(arr.unique2())