year函数 有关问题，在线给分

year函数 问题，在线给分

如$year=过的年数，如５
$staff_join=开始的年月日　如2008-05-02
我现要　把开始的年月日加上年数，如　2008-05-02＋5＝2013-05-02　用什么表达式呀，
要可运行的代码，谢谢

小弟这样　（$Begin=(date("Y",$staff_join)+$year)　出错，　输出1970）

------解决方案--------------------

PHP code

<?php $year = 5;$staff_join ="20010-05-02";$a = strtotime("+".$year." Year")-time(); $staff_join = strtotime($staff_join)+$a;echo date('Y-m-d',$staff_join);?><br><font color="#e78608">------解决方案--------------------</font><br>这里赋值写错了<br>$staff_join ="20010-05-02";<br>改成$staff_join ="2010-05-02";<br><font color="#e78608">------解决方案--------------------</font><br>

PHP code

$year = 5;$staff_join = '2008-05-02';$arrdate= explode('-',$staff_join);$arrdate[0] += $year;$staff_out = implode('-',$arrdate);echo $staff_out; //2013-05-02echo "<br>";echo $arrdate[0]; //2013?><br><font color="#e78608">------解决方案--------------------</font><br><pre class="brush:php;toolbar:false"><br><?php <br />$year = 5;<br>$staff_join='2008-05-02';<br><br>$join_date = mktime(0, 0, 0,  <br>	substr($staff_join, 5, 2), substr($staff_join, -2, 2), substr($staff_join, 0, 4));<br>echo date('Y-m-d', $join_date), "\n";<br>$join_date_5_years_later =  <br>	strtotime("+$year Year", $join_date );<br><br>echo date('Y-m-d', $join_date_5_years_later);<br>?><br>

------解决方案--------------------

PHP code

<?php $value = 5;$year = date('Y');$year += $value;echo $year.date('-m-d');<br /><font color="#e78608">------解决方案--------------------</font><br>$year = 5;  <br>$staff_join = '2008-05-02';<br><br>$Begin = date("Y-m-d", strtotime("+$year year $staff_join));<br><br><font color="#e78608">------解决方案--------------------</font><br>给楼上老大改下<br><?php   <br />$year = 5;  <br>$staff_join = '2008-05-02';  <br><br>$Begin = date("Y-m-d", strtotime("+$year year $staff_join"));  <br>echo $Begin;<br>?><br><font color="#e78608">------解决方案--------------------</font><br><?php   <br />$year = 5;  <br>$staff_join = '2008-05-02';  <br><br>$Begin = date("Y-m-d", strtotime("+$year year,$staff_join"));  <br>echo $Begin;<br>?><br><font color="#e78608">------解决方案--------------------</font><br>看来已经解决了<br><font color="#e78608">------解决方案--------------------</font><br>strtotime<br><font color="#e78608">------解决方案--------------------</font><br>老兄去研究一下strtotime函数，手册上有详细说明。<div class="clear">
                 
              
              
        
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