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HomeBackend DevelopmentPHP Tutorial关与ajax的有关问题

关与ajax的问题
var xmlHttp;
function S_xmlhttprequest(){
if(window.ActiveXObject){
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");

}
else if(window.XMLHttpRequest){
xmlHttp=new XMLHttpRequest();

}
}

function myajax(url){

S_xmlhttprequest();
xmlHttp.open("GET","for.php?id="+url,true);
xmlHttp.onreadystatechange=byphp();
xmlHttp.send(null);
}

function byphp(){

var byphp1=xmlHttp.responseText;

document.getElementById("php").innerHTML="test";
}

前面的两个函数都是对的。最后一个函数有问题。我把var byphp1=xmlHttp.responseText这句注释后最后前台可以显示test,但是加上var byphp1=xmlHttp.responseText后,就显示网页有错误。


for.php的内容是

if($id=$_GET['id']){
for($i=1;$i echo $id;
}
exit();
}
?>


------解决方案--------------------
你代码写错了?记得结贴!发了十几分钟找到错误!给你写个完整的,你的for.php页不变

PHP code
<script language="javascript">var xmlHttp;function S_xmlhttprequest(){if(window.ActiveXObject){xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");}else if(window.XMLHttpRequest){xmlHttp=new XMLHttpRequest();}}function myajax(url){S_xmlhttprequest();xmlHttp.open("GET","for.php?id="+url,true);xmlHttp.onreadystatechange=byphp;//这里不要加byphp()xmlHttp.send(null);}function byphp(){var byphp1= xmlHttp.responseText;document.getElementById("php").innerHTML=byphp1;}</script><div id="php">测试用的</div><div onclick="myajax('www.163.com')">点击触发</div><!--怀疑你这里也调用错了,你该不会去调用byphp了吧--><br><font color="#e78608">------解决方案--------------------</font><br>装火狐浏览器+firebug,可调试js哪里有错误。<div class="clear">
                 
              
              
        
            </div>
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