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HomeWeb Front-endJS TutorialCI框架实现cookie登陆的方法详解_php实例

本文实例讲述了CI框架实现cookie登陆的方法。分享给大家供大家参考,具体如下:

第一步:login.php

//登陆方法
 public function login(){
  //如果用户名和密码为空,则返回登陆页面
  if(empty($_POST['username']) || empty($_POST['password'])){
   $data['verifycode'] = rand(1000,9999);//生成一个四位数字的验证码
   //将验证码放入session中,注意:参数是数组的格式
   $this->session->set_userdata($data);
   //注意:CI框架默认模板引擎解析的模板文件中变量不需要$符号
   //$this->parser->parse("admin/login",$data);
   //smarty模板变量赋值
   $this->tp->assign("verifycode",$data['verifycode']);
   //ci框架在模板文件中使用原生态的PHP语法输出数据
   //$this->load->view('login',$data);//登陆页面,注意:参数2需要以数组的形式出现
   //显示smarty模板引擎设定的模板文件
   $this->tp->display("admin/login.php");
  }else{
   $username = isset($_POST['username'])&&!empty($_POST['username'])?trim($_POST['username']):'';//用户名
   $password = isset($_POST['password'])&&!empty($_POST['password'])?trim($_POST['password']):'';//密码
   $verifycode = isset($_POST['verifycode'])&&!empty($_POST['verifycode'])?trim($_POST['verifycode']):'';//验证码
   //做验证码的校验
   if($verifycode == $this->session->userdata('verifycode')){
    //根据用户名及密码获取用户信息,注意:参数2是加密的密码
    $user_info=$this->user_model->check_user_login($username,md5($password));
    if($user_info['user_id'] > 0){
     //将用户id、username、password放入cookie中
     //第一种设置cookie的方式:采用php原生态的方法设置的cookie的值
     //setcookie("user_id",$user_info['user_id'],86500);
     //setcookie("username",$user_info['username'],86500);
     //setcookie("password",$user_info['password'],86500);
     //echo $_COOKIE['username'];
     //第二种设置cookie的方式:通过CI框架的input类库
     $this->input->set_cookie("username",$user_info['username'],3600);
     $this->input->set_cookie("password",$user_info['password'],3600);
     $this->input->set_cookie("user_id",$user_info['user_id'],3600);
     //echo $this->input->cookie("password");//适用于控制器
     //echo $this->input->cookie("username");//适用于控制器
     //echo $_COOKIE['username'];//在模型类中可以通过这种方式获取cookie值
     //echo $_COOKIE['password'];//在模型类中可以通过这种方式获取cookie值
     //第三种设置cookie的方式:通过CI框架的cookie_helper.php函数库文件
     //这种方式不是很灵验,建议大家采取第二种方式即可
     //set_cookie("username",$user_info['username'],3600);
     //echo get_cookie("username");
     //session登陆时使用:将用户名和用户id存入session中
     //$data['username']=$user_info['username'];
     //$data['user_id']=$user_info['user_id'];
     //$this->session->set_userdata($data);
     //跳转到指定页面
     //注意:site_url()与base_url()的区别,前者带index.php,后者不带index.php
     header("location:".site_url("index/index"));
    }
   }else{
    //跳转到登陆页面
    header("location:".site_url("common/login"));
   }
  }
 }
}

第二步:User_model.php

//cookie登陆:检测用户是否登陆,如果cookie值失效,则返回false,如果cookie值未失效,则根据cookie中的用户名和密码从数据库中获取用户信息,如果能获取到用户信息,则返回查询到的用户信息,如果没有查询到用户信息,则返回0
 public function is_login(){
  //获取cookie中的值
  if(empty($_COOKIE['username']) || empty($_COOKIE['password'])){
   $user_info = false;
  }else{
   $user_info=$this->check_user_login($_COOKIE['username'],$_COOKIE['password']);
  }
  return $user_info;
 }
 //根据用户名及加密密码从数据库中获取用户信息,如果能获取到,则返回获取到的用户信息,否则返回false,注意:密码为加密密码
 public function check_user_login($username,$password){
  //这里大家要注意:$password为md5加密后的密码
  //$this->db->query("select * from ");
  //快捷查询类的使用:能为我们提供快速获取数据的方法
  //此数组为查询条件
  //注意:关联数组
  $arr=array(
   'username'=>$username,//用户名
   'password'=>$password,//加密密码
   'status'=>1   //账户为开启状态
  );
  //在database.php文件中已经设置了数据表的前缀,所以此时数据表无需带前缀
  $query = $this->db->get_where("users",$arr);
  //返回二维数组
  //$data=$query->result_array();
  //返回一维数组
  $user_info=$query->row_array();
  if(!empty($user_info)){
   return $user_info;
  }else{
   return false;
  }
}

第三步:其它控制器:

public function __construct(){
  //调用父类的构造函数
  parent::__construct();
  $this->load->library('tp'); //smarty模板解析类
  $this->load->helper('url'); //url函数库文件
  $this->load->model("user_model");//User_model模型类实例化对象
  $this->cur_user=$this->user_model->is_login();
  if($this->cur_user === false){
   header("location:".site_url("common/login"));
  }else{
   //如果已经登陆,则重新设置cookie的有效期
   $this->input->set_cookie("username",$this->cur_user['username'],3600);
   $this->input->set_cookie("password",$this->cur_user['password'],3600);
   $this->input->set_cookie("user_id",$this->cur_user['user_id'],3600);
  }
  $this->load->library('pagination');//分页类库
  $this->load->model("role_model");//member_model模型类
  $this->load->model("operation_model");//引用operation_model模型
  $this->load->model("object_model");//引用object_model模型
  $this->load->model("permission_model");//引用permission_model模型
}

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希望本文所述对大家基于CodeIgniter框架的PHP程序设计有所帮助。

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