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Javascript imitates PHP $_GET to get the parameters in the URL_javascript skills

WBOY
WBOYOriginal
2016-05-16 16:48:401286browse

复制代码 代码如下:

/* 像PHP的 $_GET['arg'] 那样获得地址栏GET参数 */
function getArgs() {
    var args = {};
    var query = location.search.substring(1); // Get query string
    var pairs = query.split("&");
                   // Break at ampersand
     for(var i = 0; i < pairs.length; i ) {
            var pos = pairs[i].indexOf('=');
             // Look for "name=value"
            if (pos == -1) continue;  // If not found, skip
               var argname = pairs[i].substring(0,pos); // Extract the name
               var value = pairs[i].substring(pos 1); // Extract the value
               value = decodeURIComponent(value); // Decode it, if needed
               args[argname] = value;  // Store as a property
        }
    return args; // Return the object          
}

/* 使用方法 */
/* URL: http://www.baidu.com?user=funsion&age=26 */
alert( getArgs()['user'] );  // 输出 funsion
alert( getArgs()['age'] );  // 输出 26

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