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http://blog.sina.com.cn/s/blog_53636a020100f93i.html Oracle中INSTR和SUBSTR的用法 Oracle中INSTR的用法: INSTR方法的式为 INSTR(源字符串, 要查找的字符串, 从第几个字符开始, 要找到第几个匹配的序号) 返回找到的位置,如果找不到则返回0. 例如:INSTR

http://blog.sina.com.cn/s/blog_53636a020100f93i.html


Oracle中INSTR和SUBSTR的用法

Oracle中INSTR的用法:
INSTR方法的格式为
INSTR(源字符串, 要查找的字符串, 从第几个字符开始, 要找到第几个匹配的序号)
返回找到的位置,如果找不到则返回0.
例如:INSTR('CORPORATE FLOOR','OR', 3, 2)中,源字符串为'CORPORATE FLOOR',在字符串中查找'OR',从第三个字符位置开始查找"OR",取第三个字后第2个匹配项的位置。

默认查找顺序为从左到右。当起始位置为负数的时候,从右边开始查找。

所以SELECT INSTR('CORPORATE FLOOR', 'OR', -1, 1) "aaa" FROMDUAL的显示结果是

Instring
——————
14


oracle的substr函数的用法:
 取得字符串中指定起始位置和长度的字符串  substr( string, start_position, [ length ] )
 如:
    substr('This is a test', 6,2)    would return 'is'
    substr('This is a test',6)    would return 'is a test'
    substr('TechOnTheNet', -3,3)    would return 'Net'
    substr('TechOnTheNet', -6,3)    would return 'The'
 
select substr('Thisisatest', -4, 2) value from dual


综合应用:
SELECT INSTR('CORPORATE FLOOR', 'OR', -1, 1) "Instring" FROMDUAL
--INSTR(源字符串, 目标字符串, 起始位置, 匹配序号)
SELECT INSTR('CORPORATE FLOOR','OR', 3, 2) "Instring" FROM DUAL

SELECT INSTR('32.8,63.5',',', 1, 1) "Instring" FROM DUAL

SELECT SUBSTR('32.8,63.5',INSTR('32.8,63.5',',', 1, 1)+1)"INSTRING" FROM DUAL
SELECT SUBSTR('32.8,63.5',1,INSTR('32.8,63.5',',', 1, 1)-1)"INSTRING" FROM DUAL

-- CREATED ON 2008-9-26 BY ADMINISTRATOR
DECLARE
  -- LOCAL VARIABLES HERE
  VARCHAR2(2000);
  VARCHAR2(2000);
  NUM INTEGER;
  INTEGER;
  POS INTEGER;
BEGIN
  -- TEST STATEMENTS HERE
  T := '12.3,23.0;45.6,54.2;32.8,63.5;';
  SELECT LENGTH(T) - LENGTH(REPLACE(T, ';', ''))INTO NUM FROM DUAL;
  DBMS_OUTPUT.PUT_LINE('NUM:' || NUM);
  POS := 0;
  FOR I IN 1 .. NUM LOOP
   DBMS_OUTPUT.PUT_LINE('I:' || I);
   DBMS_OUTPUT.PUT_LINE('POS:' || POS);
   DBMS_OUTPUT.PUT_LINE('==:' || INSTR(T, ';', 1, I));
   DBMS_OUTPUT.PUT_LINE('INSTR:' || SUBSTR(T, POS + 1, INSTR(T, ';',1, I) - 1));
    POS :=INSTR(T, ';', 1, I);
  END LOOP;
END;


-- Created on 2008-9-26 by ADMINISTRATOR
declare
  -- Local variables here
  i integer;
     VARCHAR2(2000);
     VARCHAR2(2000);
begin
  -- Test statements here
    --历史状态
  T := '12.3,23.0;45.6,54.2;32.8,63.5;';
  IF (T IS NOT NULL) AND (LENGTH(T)> 0) THEN
    --T := T ||',';
    WHILELENGTH(T) > 0 LOOP
     --ISTATUSID := 0;
            := TRIM(SUBSTR(T, 1, INSTR(T, ';') - 1));
     IF LENGTH(S) > 0 THEN
        DBMS_OUTPUT.PUT_LINE('LAT:'||SUBSTR('32.8,63.5',1,INSTR('32.8,63.5',',',1, 1)-1));
        DBMS_OUTPUT.PUT_LINE('LON:'||SUBSTR('32.8,63.5',INSTR('32.8,63.5',',',1, 1)+1));
       -- COMMIT;
     END IF;
     T := SUBSTR(T, INSTR(T, ';') + 1);
    ENDLOOP;
  END IF; 
end;


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