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如何用Ajax CI实现 关注好友 功能

WBOY
WBOYOriginal
2016-06-06 20:52:09855browse

<div id="follow"><a href="#" class="follow <?php if($selfollow > 0){echo 'message';}?>"><?php if($selfollow == 0){echo '关注';}else{echo '取消关注';}?></a></div>

上面是HTML

$('#follow').click(function(){
if($(".follow").text() == "关注")
{   
    var form_data = {
        pid:<?php echo $selproduct['pid'];?>,
        ajax:'1'
    };

    $.ajax({
        url:"<?php echo site_url('welcome/addfollow/');?>",
        type:'POST',
        data:form_data,
        success:function(msg){
             $('#follow').html();
        }
    });
}
else
{
    var form_data = {
        pid:<?php echo $selproduct['pid'];?>,
        ajax:'1'
    };

    $.ajax({
        url:"<?php echo site_url('welcome/delfollow/');?>",
        type:'POST',
        data:form_data,
        success:function(msg){
            $('#follow').html(msg);
        }
    });

}
return false;
})

上面是我写的jquery代码,功能实现了,但是为什么只有等手动刷新本页面才能看到结果呢?
下面的 CI控制器的写法,求指导。。

function addfollow(){
    $pid = $this->input->post('pid');
    if($this->input->post('ajax')){
    }
}

回复内容:

<div id="follow"><a href="#" class="follow <?php if($selfollow > 0){echo 'message';}?>"><?php if($selfollow == 0){echo '关注';}else{echo '取消关注';}?></a></div>

上面是HTML

$('#follow').click(function(){
if($(".follow").text() == "关注")
{   
    var form_data = {
        pid:<?php echo $selproduct['pid'];?>,
        ajax:'1'
    };

    $.ajax({
        url:"<?php echo site_url('welcome/addfollow/');?>",
        type:'POST',
        data:form_data,
        success:function(msg){
             $('#follow').html();
        }
    });
}
else
{
    var form_data = {
        pid:<?php echo $selproduct['pid'];?>,
        ajax:'1'
    };

    $.ajax({
        url:"<?php echo site_url('welcome/delfollow/');?>",
        type:'POST',
        data:form_data,
        success:function(msg){
            $('#follow').html(msg);
        }
    });

}
return false;
})

上面是我写的jquery代码,功能实现了,但是为什么只有等手动刷新本页面才能看到结果呢?
下面的 CI控制器的写法,求指导。。

function addfollow(){
    $pid = $this->input->post('pid');
    if($this->input->post('ajax')){
    }
}

好吧,问题我自己解决了 要感谢@joyqi 的提示
主要是是操作数据的时候没有返回值, $ajax重写一定要这样写

success:function(msg){

  $('#follow').html(msg);

}

返回的#follow 要单独写一个文件

CI 控制器要这样写:

function addfollow(){


$pid = $this->input->post('pid');


if($this->input->post('ajax')){

$data['pid'] = $pid;

$this->load->view('follow', $data);

}


}

你ajax返回的应该是当前返回数吧,你看看你follow的js代码里

success:function(msg){
             $('#follow').html();
        }

这里应该是$('#follow').html(msg);

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