Instructions for using the url.parse method in node.js_node.js

Method description:

Convert a URL string into an object and return it.

Grammar:

Copy code The code is as follows:

url.parse(urlStr, [parseQueryString], [slashesDenoteHost])

Receive parameters:

urlStr URL string

parseQueryString When it is true, the query module will be used to analyze the query string. The default is false

slashesDenoteHost    

The default is false, a string in the form //foo/bar will be interpreted as { pathname: ‘//foo/bar’ }

If set to true, a string of the form //foo/bar will be interpreted as { host: ‘foo’, pathname: ‘/bar’ }

Example:

Copy code The code is as follows:

var url = require('url');
var a = url.parse('http://example.com:8080/one?a=index&t=article&m=default');
console.log(a);

//Output result:
{
Protocol: 'http' ,
auth : null ,
Host : 'example.com:8080' ,
Port: '8080' ,
Hostname : 'example.com' ,
hash : null ,
Search : '?a=index&t=article&m=default',
Query : 'a=index&t=article&m=default',
Pathname : '/one',
Path: '/one?a=index&t=article&m=default',
href : 'http://example.com:8080/one?a=index&t=article&m=default'
}