下面是,http_header
php 代码:
<code><?php echo var_dump($_POST); echo '<br>'+ var_dump($_REQUEST) + '<br>' ; ?></code>
回复内容:
下面是,http_header
php 代码:
<code><?php echo var_dump($_POST); echo '<br>'+ var_dump($_REQUEST) + '<br>' ; ?></code>
<code><?php echo var_dump($_POST); echo '<br>'+ var_dump($_REQUEST) + '<br>' ; ?></code>
以后调试像下面这样就可以了
<code><?php var_dump($_POST); var_dump($_REQUEST) ; ?></code>
此外。PHP中的连字符用点号 . 不用加号+
试试 var_dump(file_get_contents('php://input'));
看 Response 有没有数据, 如果有, 说明 异步有处理, 需要在 ajax回调处理。。。如果没有,继续看看 ajax 地址是不是有问题
1.检查下form 表单 提交的路径是否正确
2.检查下表单元素的name 属性是否有值.
你用Ajax发送的时候,如果不用jQuery,那你得给你的form data编码。你可以参考jQuery.param

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