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Home >Backend Development >PHP Tutorial >我想让这个blog.php页面把登陆的用户名打印出来应该怎么写呢？

我想让这个blog.php页面把登陆的用户名打印出来应该怎么写呢？

WBOY
WBOYOriginal
2016-06-06 20:18:41860browse

blog.php

<code> <?php include "cookie.php";
    ?></code>

cookie页面

<code><?php if(!(isset($_COOKIE['isLogin'])&&$_COOKIE['isLogin']==1)){
     echo '您还没有登陆呢！请您登陆';
 }else{
    echo '您是登陆的';
 }
?>
</code>

login.php

<code><?php $pdo=new PDO("mysql:host=localhost;dbname=t1;","root","");
 if(isset($_POST['submit'])){
 $stmt=$pdo->prepare("select id,username,password from user where username=? and password=?");
 $stmt->execute(array($_POST['username'],($_POST['password'])));
 if($stmt->rowCount()>0){
 list($id,$username)=$stmt->fetch(PDO::FETCH_NUM);
   $time=time()+24*60*60;
   setCookie("uid",$id,$time,"/");
   setCookie("username",$username,$time,"/");
   setCookie("isLogin",1,$time,"/");
   echo '<script>location="blog.php"</script>';
 }
 else{
     echo "登陆失败";
 }
 }
?>




<form action="login.php" method="post">
用户名：<input type="text" name="username">
密码：<input type="text" name="password">
<button type="submit" name="submit">登录</button>
</form>

</code>

回复内容：

blog.php

<code> <?php include "cookie.php";
    ?></code>

cookie页面

<code><?php if(!(isset($_COOKIE['isLogin'])&&$_COOKIE['isLogin']==1)){
     echo '您还没有登陆呢！请您登陆';
 }else{
    echo '您是登陆的';
 }
?>
</code>

login.php

<code><?php $pdo=new PDO("mysql:host=localhost;dbname=t1;","root","");
 if(isset($_POST['submit'])){
 $stmt=$pdo->prepare("select id,username,password from user where username=? and password=?");
 $stmt->execute(array($_POST['username'],($_POST['password'])));
 if($stmt->rowCount()>0){
 list($id,$username)=$stmt->fetch(PDO::FETCH_NUM);
   $time=time()+24*60*60;
   setCookie("uid",$id,$time,"/");
   setCookie("username",$username,$time,"/");
   setCookie("isLogin",1,$time,"/");
   echo '<script>location="blog.php"</script>';
 }
 else{
     echo "登陆失败";
 }
 }
?>




<form action="login.php" method="post">
用户名：<input type="text" name="username">
密码：<input type="text" name="password">
<button type="submit" name="submit">登录</button>
</form>

</code>

setCookie("username",$username,$time,"/");

<code>echo $username;//打印用户名</code>
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