仲颖**5年前

见PPT 将直接量字符单独放进[]中就组成字符类，一个字符类可以匹配它所包含的任意一个字符，[]就是用于查找某个范围内的字符， Chrome本来就支持多行模式。 一行模式直接按回车就会执行并输出结果。如果多行模式就按shfit+回车键 等你输入完了再回车就行了。希望能帮到你。 总结一句话：shfit+回车键 就是多行js模式 测试： var str="Hello World! Welcome to php.cn123" var a=/[0-9]/ var b=/[a-z]/ var c=/[A-Z]/ var d=/[a-zA-Z0-9]/ undefined a.exec(str) ["1", index: 30, input: "Hello World! Welcome to php.cn123", groups: undefined] b.exec(str) ["e", index: 1, input: "Hello World! Welcome to php.cn123", groups: undefined] c.exec(str) ["H", index: 0, input: "Hello World! Welcome to php.cn123", groups: undefined] d.exec(str) ["H", index: 0, input: "Hello World! Welcome to php.cn123", groups: undefined] var str1="Hello World! Welcome to php.cn123" undefined var aa=/l+/ //全局匹配 undefined str1.match(aa) ["ll", index: 2, input: "Hello World! Welcome to php.cn123", groups: undefined] var a1=/l+/g //全局匹配 str1.match(a1) (3) ["ll", "l", "l"] var b1=/\w/g //全局匹配 str1.match(b1) (27) ["H", "e", "l", "l", "o", "W", "o", "r", "l", "d", "W", "e", "l", "c", "o", "m", "e", "t", "o", "p", "h", "p", "c", "n", "1", "2", "3"] var b1=/\w+/g //全局匹配 str1.match(b1) (6) ["Hello", "World", "Welcome", "to", "php", "cn123"] var c1=/lo*/g str1.match(c1) (4) ["l", "lo", "l", "l"] var c1=/lo?/g str1.match(c1) (4) ["l", "lo", "l", "l"] var st="1000 100 1234 12 5000" var b=/\d{4}/ //查找4位数的数字 undefined var st="1000 100 1234 12 5000" var b=/\d{4}/g //查找4位数的数字 st.match(b) (3) ["1000", "1234", "5000"] var st="1000 100 1234 12 5000" var b=/\d{3,4}/g //查找4位数的数字 st.match(b) (4) ["1000", "100", "1234", "5000"] var st="1000 100 1234 12 5000 456 7 23 899" var b=/\d{3,}/g //查找至少是3位数的数字 st.match(b) (6) ["1000", "100", "1234", "5000", "456", "899"] var str="Isthisallthereis" var a=/is(?=all)/g str.match(a) ["is"] var str="Isthisallthereis" var a=/is(?!all)/g //注意，这里返回的是thereis的is str.match(a) ["is"] var str="Isthisallthereis" var b=/is(?!all)/g //注意，这里返回的是thereis的is str.match(b) ["is"] str.search(b) 14 var str="Isthisallthereis" var a=/is(?=all)/g str.match(a) ["is"] str.search(a) 4

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