以前听老师讲过sprintf()函数需要使用echo方 法才可以讲格式化后的字符串显示输出,下面我来看一下简单的方法.
我在阅读一些资料,书籍的时候总是总是会看到如下这样的代码
实例代码如下:
$query = sprintf('INSERT INTO %sUSER (USERNAME, PASSWORD, ' .
'EMAIL_ADDR, IS_ACTIVE, PERMISSION) VALUES ("%s", "%s", "%s", %d, %d)',
DB_TBL_PREFIX,
mysql_real_escape_string($this->username, $GLOBALS['DB']),
mysql_real_escape_string($this->password, $GLOBALS['DB']),
mysql_real_escape_string($this->emailAddr, $GLOBALS['DB']),
$this->isActive,
$this->permission);这边使用了sprintf来格式化字符串,这样的写法和直接用字符串连接符连接起来的写法有什么区别吗.或者说这样更加严谨
printf()函数与sprintf()函数的语法格式为:
int printf(string $format[,mixed $arg1[,mixed args2...]]) string sprintf(string $format[,mixed $arg1[,mixed args2...]])
一个小例子,实例代码如下:
PHP中echo,print,printf,sprintf的区别
<?PHP $str='let\'s study php!'; echo $str."<br/>"; $number=print $str."<br/>"; echo $number."<br/>"; $format="%b%c%d"; $number1=printf($format,88,88,88); echo "<br/>".$number1; echo "<br/>".sprintf($format,88,88,88); ?>
echo,print,printf,sprintf的介绍
print输出方式的返回值为int类型的,返回值永远是1,print的语法格式如下:
int print(string $str)
echo输出方式是没有返回值的,echo的语法格式如下:
void echo(string $str[,string $str1...])
在PHP中,一般情况下echo和print是可以通用的,但是在某些情况下两种方式也是有区别的,具体表现在:
1)echo支持多个参数,但是print只支持一个参数
2)echo返回值为void,print有一个永远为1的返回值
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