现在有一个json数据,
如下:
{
"favourite":{
"bkmrk":{
"id1490843709594066":{
"guid":"904eff52277f403b89f6410fe2758646.11",
"lcate":"1"
},
"id1490843712805183":{
"guid":"58457f60eca64025bc43a978f9c98345.16",
"lcate":"2"
},
"id149084371467327":{
"guid":"a0f907f9dc8b40f689b083f3eba7228b.16",
"lcate":"3"
},
"id1490843716295393":{
"guid":"eb75d929455e468bb712e7bc2025d11a.16",
"lcate":"4"
}
}
}
}
我该如何使用python操作该json,才能输出所有的guid和lcate有序对,即以下形式:
1;904eff52277f403b89f6410fe2758646.11
2;58457f60eca64025bc43a978f9c98345.16
3;a0f907f9dc8b40f689b083f3eba7228b.16
4;eb75d929455e468bb712e7bc2025d11a.16
非常感谢。
PHP中文网2017-04-18 10:32:12
json_dict = json.loads(json_str)
for item in json_dict['favourite']['bkmrk']:
guid = json_dict['favourite']['bkmrk'][item]['guid']
lcate = json_dict['favourite']['bkmrk'][item]['lcate']
print '%s:%s' % (lcate,guid)
反正都是字典,不要想那么多
怪我咯2017-04-18 10:32:12
使用json包中的json.loads将该字符串转换为Python字典。 代码如下:
import json
json_data = """{
"favourite":{
"bkmrk":{
"id1490843709594066":{
"guid":"904eff52277f403b89f6410fe2758646.11",
"lcate":"1"
},
"id1490843712805183":{
"guid":"58457f60eca64025bc43a978f9c98345.16",
"lcate":"2"
},
"id149084371467327":{
"guid":"a0f907f9dc8b40f689b083f3eba7228b.16",
"lcate":"3"
},
"id1490843716295393":{
"guid":"eb75d929455e468bb712e7bc2025d11a.16",
"lcate":"4"
}
}
}
}"""
data = json.loads(json_data)
for v in data['favourite']['bkmrk'].values():
print("%s;%s" % (v['lcate'], v['guid']))