尝试连接 119.23.124.81:7575
服务器每5秒会返回一个{"type":"ping"}
,我尝试用以下代码去连接,但是无法获取到这个{"type":"ping"}
:
s = socket(AF_INET, SOCK_STREAM)
# 建立连接:
s.connect(('119.23.124.81', 7575))
while True:
print(s.recv(1024).decode('utf-8'))
s.close()
代码不会报错,但是也获取到我想要的内容
请问要如何写才能获取到这个{"type":"ping"}
大家讲道理2017-04-18 10:27:11
搞清楚了,原来这个是使用的websocket协议,不是普通的socket
换用websocket这个库就好了,代码如下:
from websocket import create_connection
ws = create_connection("ws://42.96.131.185:7575")
print("Sending 'Hello, World'...")
for i in range(10000):
ws.send(b"Hello, World")
print("Sent")
print("Reeiving...")
result = ws.recv()
print("Received '%s'" % result)
ws.close()
迷茫2017-04-18 10:27:11
参考官方文档
# Echo server program
import socket
HOST = '' # Symbolic name meaning all available interfaces
PORT = 50007 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
data = conn.recv(1024)
if not data: break
conn.sendall(data)
conn.close()
and
import SocketServer
class MyTCPHandler(SocketServer.BaseRequestHandler):
"""
The request handler class for our server.
It is instantiated once per connection to the server, and must
override the handle() method to implement communication to the
client.
"""
def handle(self):
# self.request is the TCP socket connected to the client
self.data = self.request.recv(1024).strip()
print "{} wrote:".format(self.client_address[0])
print self.data
# just send back the same data, but upper-cased
self.request.sendall(self.data.upper())
if __name__ == "__main__":
HOST, PORT = "localhost", 9999
# Create the server, binding to localhost on port 9999
server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
# Activate the server; this will keep running until you
# interrupt the program with Ctrl-C
server.serve_forever()
PHP中文网2017-04-18 10:27:11
因为你发送的数据是一个字典对象,所以在socket发送据时,用pickle或者json模块对数据进行序列化再发送,对应的,接收端要用pickle或者json进行反序列化操作。