android - Error: java.lang.IndexOutOfBoundsException: Invalid index 2

Question

How to remove the seperator line in footerLayout? I have a footerLayout below the listView, used to display the totalAmount as shown below. If I click the seperator line in footerLayout, my app crashed.

My MainActivity

AllAdapter obj = new AllAdapter(getApplication(), search, listview,imageView,text,button);
footerLayout = (LinearLayout) getLayoutInflater().inflate(R.layout.under_listview, null);
totalAmount = (TextView) footerLayout.findViewById(R.id.amount);

LogCat error

 java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2
            at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
            at java.util.ArrayList.get(ArrayList.java:304)
            at com.example.tony.monthlyexpenses.adapter.AllAdapter.getItem(AllAdapter.java:61)
            at com.example.tony.monthlyexpenses.QuickExpenses$1.onItemClick(QuickExpenses.java:88)
            at android.widget.AdapterView.performItemClick(AdapterView.java:301)

The error pointed to listView onClickListener

 listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                mClickedPosition = position;
                Expenses o = (Expenses) obj.getItem(position);
                String day = o.getDate();
            }
        });

AllAdapter

 public Expenses getItem(int position) {
        return search.get(position);
    }

The footerLayout is supposed to be displayed outside the listView, not inside. How can I get rid of this ?

I also have activity_main.xml, AllAdapter class, all_adapter.xml for ListView and also under_listview.xml for the footerLayout.

activity_main

AllAdapter

under_listview

How to move the footerLayout out from the ListView ?

I add android:footerpidersEnabled="false" now become like this

But still clickable !!!

谁知道问题出在哪？

footerLayout被按时如何不出现灰色？

Answer 1

很简单，但也很容易出错的问题，加了footer后，你的listview item数量是3，但adapter的viewcount其实并没有变成3，所以在你点击footer时执行的是obj.getItem(2)，肯定是数组越界异常了。对于添加了header或footer的listview，正确的取item方法应该是footer后，你的listview item数量是3，但adapter的viewcount其实并没有变成3，所以在你点击footer时执行的是obj.getItem(2)，肯定是数组越界异常了。对于添加了header或footer的listview，正确的取item方法应该是

listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                Expenses o = (Expenses) listView.getAdapter().getItem(position);
                if(o != null){
                    mClickedPosition = position;
                    //Expenses o = (Expenses) obj.getItem(position);
                    String day = o.getDate();
                }
            }
        });

header或footer属于AdapterView的子view，listView.getAdapter().getItem(position); rrreee

header或footer属于AdapterView的子view，listView.getAdapter().getItem(position);能确保你取2的position时不越界，再做对象空判断。🎜

Answer 2

你不能使用setOnItemClickListener 来作为footview的点击事件，我认为你应该单独的去设置
例如 footview.setonClickListener(new OnClickListener{}); 祝你好运

Answer 3

你这个是数组下标越界了啊，你的数组size是2，所以对应的下标只能是0和1，但是你在使用的时候用了2，错误显示你有个无效的index 2，你自己找下第61行和第88行，看是否有地方调用了index是2的

Answer 4

将footerLayout移出listView的写法是footerLayout移出listView的写法是

listview.addFooterView(footerLayout, null, false);

listview.addFooterView(footerLayout, null, false);🎜