比如这样的接口
http://www.xxx.com/xxx/xxx
post方式传
token="xxx"
param="{user:{id:xxx,name:xxx},order:{id:xxx}}"
用retrofit 该怎么传?
我现在的方法
表单形式上传
@Field("token") string token
@Field("param") string param
迷茫2017-04-17 17:56:03
将需要请求的数据定义成一个实体类
public class CustomBody {
public String token;
public User user;
public Order order;
public CustomBody(String token, User user, Order order) {
this.token = token;
this.user = user;
this.order = order;
}
public static class Order {
public String id;
public Order(String id) {
this.id = id;
}
}
public static class User {
public String id;
public String name;
public User(String id, String name) {
this.id = id;
this.name = name;
}
}
}
Retrofit 的 Service 这样子写就可以了,使用 @Body
注解@Body
注解
public interface MyService {
@POST("/")
Observable<T> access(@Body CustomBody customBody);
}
使用 HttpLoggingInterceptor
OkHttpClient.interceptors().add(new HttpLoggingInterceptor());
使用 HttpLoggingInterceptor
可以在 log 中查看 HTTP 请求的详细情况。🎜
11-19 16:58:46.495 4591-4612/? D/OkHttp: --> POST / HTTP/1.1
11-19 16:58:46.495 4591-4612/? D/OkHttp: {"order":{"id":"1"},"token":"123","user":{"id":"1","name":"name"}}
11-19 16:58:46.495 4591-4612/? D/OkHttp: --> END POST (66-byte body)
rrreee