首页  >  问答  >  正文

MySQL 查询每日每小时峰值

现在的查询方法是这样的:

SELECT COUNT(r.user_id) AS users
FROM record r
WHERE r.created BETWEEN :date_from AND :date_till
GROUP BY HOUR(r.created)
ORDER BY users DESC
LIMIT 1

但这样如果查询多天的峰值就要循环执行多次查询,是否有更高效的方法?

黄舟黄舟2718 天前312

全部回复(1)我来回复

  • 天蓬老师

    天蓬老师2017-04-17 11:26:34

    假设 r.created 是类似 2014-04-03 09:04:00

    SELECT COUNT(r.user_id) AS users, HOUR(r.created) data_hour, FROM_UNIXTIME(unix_timestamp(r.created), "%Y-%m-%d") data_date
    FROM record r
    WHERE r.created BETWEEN :date_from AND :date_till
    GROUP BY data_hour, data_date
    ORDER BY data_date, users, data_hour DESC
    

    回复
    0
  • 取消回复