SQL中使用UNION对两个查询结果进行数据透视

Question

我正在尝试从 MySql 数据库获取两个查询结果的数据透视表

这是我的 SQL 查询：

SELECT * FROM (
SELECT 'NotSpot' as NotSpot,SUM(builds.Duration) as Duration , DATE_FORMAT(builds.date, "%Y-%c-%d") as date
FROM builds JOIN labels ON builds.Labels_label_id = labels.label_id
JOIN CITools ON CITools.tool_id=labels.CITools_tool_id
WHERE labels.label_name NOT LIKE '%SPOT%' AND CITools.tool_name='jenkins' AND builds.date AND builds.date >= '2022-03-01' AND builds.date <= '2022-03-10' 
GROUP BY DAY(date)

UNION ALL

SELECT 'Spot' as Spot,SUM(builds.Duration) as Duration , DATE_FORMAT(builds.date, "%Y-%c-%d") as date
FROM builds JOIN labels ON builds.Labels_label_id = labels.label_id
JOIN CITools ON CITools.tool_id=labels.CITools_tool_id
WHERE labels.label_name LIKE '%SPOT%' AND CITools.tool_name='jenkins' AND builds.date AND builds.date >= '2022-03-01' AND builds.date <= '2022-03-10' 
GROUP BY DAY(date)
) result

这就是结果：

__________________________________
NotSpot  |  Duration  |  date
________  __________   ______
NotSpot  1756343919   2022-03-01
NotSpot  1710800867   2022-03-02
NotSpot  1672806894   2022-03-03
NotSpot  859574350    2022-03-04
.         .            .
.         .            .
.         .            .
Spot      693071042     2022-03-01
Spot      728884095     2022-03-02
Spot      872995684     2022-03-03
.         .             .
.         .             .
.         .             .
__________________________________

我想要的结果：

_______________________________________________
NotSpot Duration  |  Spot Duration  |  date     
__________________  ________________  _________
    1756343919       1756343919       2022-03-01
    1710800867       1672806894       2022-03-02
    1672806894       859574350        2022-03-03
    859574350        4267822656       2022-03-04
       .                 .                  .
       .                 .                  .
       .                 .                  .
________________________________________________

你能帮我得到这个结果吗？ 预先感谢您。

Answer 1

您始终可以使用 case 函数来模拟数据透视表

select
    sum(case result.NotSpot when 'NotSpot' then result.Duration end) as NotSpot_Duration,
    sum(case result.NotSpot when 'Spot' then result.Duration end) as Spot_Duration,
    result.date
from result
group by result.date

其中“结果”正是您的查询

Answer 2

使用case 表达式进行条件聚合：

SELECT SUM(case when labels.label_name NOT LIKE '%SPOT%' then builds.Duration else 0 end) as notspot,
       SUM(case when labels.label_name LIKE '%SPOT%' then builds.Duration else 0 end) as spot, 
       DATE_FORMAT(builds.date, "%Y-%c-%d") as date
FROM builds JOIN labels ON builds.Labels_label_id = labels.label_id
JOIN CITools ON CITools.tool_id=labels.CITools_tool_id
WHERE CITools.tool_name='jenkins' AND builds.date AND builds.date >= '2022-03-01' AND builds.date <= '2022-03-10' 
GROUP BY DAY(date)