我收到此错误:警告:第 21 行 C:\xampp\htdocs\BNP\Login.php 中未定义变量 $loginUser 用户名不存在。我尝试了其他修复,但它返回相同的错误消息。有人可以帮忙吗?
<?php //variables for connecting to DB $servername = "localhost"; $username = "root"; $password = ""; $dbname = "unityaccess"; //variables submitted by user if(isset($_POST['loginUser'])){ $loginUser = $_POST['loginUser']; } if(isset($_POST['loginPass'])){ $loginPass = $_POST['loginPass']; } // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT password FROM users WHERE username = '" . $loginUser . "'"; $result = $conn->query($sql); if ($result->num_rows > 0){ // output data of each row while($row = $result->fetch_assoc()) { if($row["password"] == $loginPass){ echo "Login Success, welcome."; } else { echo "Wrong Credentials"; } } } else { echo "Username does not exists"; } $conn = null; ?>
谢谢
P粉1186987402024-03-30 20:33:44
您的 $loginUser 未定义,还要检查您的表单名称属性是否有“loginUser”,并使用此更新的代码,我在其中定义了 $loginUser ,它将起作用。
connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT password FROM users WHERE username = '" . $loginUser . "'"; $result = $conn->query($sql); if ($result->num_rows > 0){ // output data of each row while($row = $result->fetch_assoc()) { if($row["password"] == $loginPass){ echo "Login Success, welcome."; } else { echo "Wrong Credentials"; } } } else { echo "Username does not exists"; } $conn = null; ?>